Originally posted by Coletti
You don't' understand what you read! 🙂
What is "special" about the fifth postulate is it could not be proven as a theorem.
[b]Euclid's fifth postulate cannot be proven as a theorem, although this was attempted by many people.
- http://mathworld.wolfram.com/EuclidsPostulates.html
[/b]Euclidean Geometry is the set of logical consequences of the five postulates we're talking about, as well as some simpler assumptions which, if we were not being careful, would be called trivial.
The fifth postulate, especially the formulation given by Euclid, is subjectively more complicated than the other four, so people wondered whether it was actually a theorem and not a postulate, and tried to deduce it from the other four.
A few people (Nikolai Lobatchevsky and Bernhard Riemann, specifically) proved that rather than being a theorem (a consequence of the other four postulates), the fifth postulate is indeed a postulate (ie completely
unspecial in comparison to the others). They did this by modifying it while leaving the other four invariant, which created new geometries (sets of internally consistent consequences of the first four postulates and some fifth postulate contradicting 'the' fifth posulate).
Thus, we have that the First Four and The Fifth together give a geometry with no internal contradictions (Euclidean geometry). The First Four and ~The Fifth give a geometry with no internal contradictions (Riemann or Lobatchevsky geometry, depending on how The Fifth gets contradicted). Thus the First Four do not imply The Fifth.
Therefore, you are indeed correct that the fifth postulate cannot be deduced from the other four, but none of the other four can be deduced from any combination of the others either.
EDIT: Exercise: What's wrong with the following reasoning?
Claim: Euclid's 2nd postulate, 'Any line segment defines a unique line' is not a postulate but a theorem.
'Proof': Suppose we have a line segment PQ. Choose some point R not on PQ. By the fifth postulate, there exists a unique line through R parallel to PQ; call it L. By the fifth postulate, there exists a unique line parallel to L through P, which we call L'. Since L is parallel to PQ and L is parallel to L', L' is parallel to PQ. But L and PQ have a point P in common and are parallel, so L is the unique line containing PQ.