Originally posted by SwissGambit1. bxa6+ [en passant] b5
[fen]Nq2k1rN/1Pb1pppr/1p4p1/pP6/Bn6/1pP4P/4P2P/R3K2R w[/fen]
White mates in 9
2. Bxb5+ Nc6
3. Bxc6+ Kf8 [3. ... Kd8 4. Nxf7 mate]
4. Nxg6+ fxg6
5. O-O+ Bf4
6. Rxf4+ Qxf4
7. b8=Q+ Qxb8 [7. ... Kf7 8. Qxf4+ Ke6 9. Nc7 mate]
8. Rf1+ Qf4
9. Rxf4 mate.
Originally posted by heinzkatWhilst Qxg6 is obviously the easiest way to mate, Bd6 is also winning and is even also forced mate.
[fen]r1b1rqk1/5p2/5Pp1/ppp1B1Q1/8/1P1P3R/P5PP/5RK1 w - -[/fen]
White to move. How to continue the attack properly?
1. Bd6 Re5 [ ... Qg7 2. Rh6 Bf5 3. fxg7 Kxg7 4. Qh4 f6 5. Rh7+ Kg8 6. Qh6 and black can only delay mate by blocking the 7th rank]
2. Qxe5 Bxh3
3. Bxf8 Kxf8
4. Rf4 Kg8
5. Qe3 Bf5
6. Rxf5 Kh7
7. Qh3+ Kg8
8. Qh6 any
9. Qg7#
There are various different moves black can play but all lead to mate in 10 or fewer.
Originally posted by PaddyBI'd have to check that. In a game I would play Qxg6+ though!
Whilst Qxg6 is obviously the easiest way to mate, Bd6 is also winning and is even also forced mate.
1. Bd6 Re5 [ ... Qg7 2. Rh6 Bf5 3. fxg7 Kxg7 4. Qh4 f6 5. Rh7+ Kg8 6. Qh6 and black can only delay mate by blocking the 7th rank]
2. Qxe5 Bxh3
3. Bxf8 Kxf8
4. Rf4 Kg8
5. Qe3 Bf5
6. Rxf5 Kh7
7. Qh3+ Kg8
8. Qh6 any
9. Qg7#
There are various different moves black can play but all lead to mate in 10 or fewer.
What if just 1. ... a4? 2. Bxf8 and a mate via Qh6-g7. Of course, there will be a win very soon, but far too many variations and subvariations to work out!!
Originally posted by heinzkatSome people think they can just take en passant whenever two pawns of opposite color are sitting next to each other on the 5th [or 4th] rank... [Or take based on the reputation of the poster!] 😞
1. bxa6+ [en passant] b5
2. Bxb5+ Nc6
3. Bxc6+ Kf8 [3. ... Kd8 4. Nxf7 mate]
4. Nxg6+ fxg6
5. O-O+ Bf4
6. Rxf4+ Qxf4
7. b8=Q+ Qxb8 [7. ... Kf7 8. Qxf4+ Ke6 9. Nc7 mate]
8. Rf1+ Qf4
9. Rxf4 mate.
Originally posted by SwissGambitI also just assumed I had the right to castle Kingside. (otherwise you wouldn't have claimed there was a mate in nine available)
Some people think they can just take en passant whenever two pawns of opposite color are sitting next to each other on the 5th [or 4th] rank... [Or take based on the reputation of the poster!] 😞
Originally posted by heinzkatThat's a more reasonable assumption. Castling requires specific proof that the King or Rook have moved for it not to be possible. Castling rights are commonly preserved over the course of several moves [sometimes complete games]. En Passant, however, is legal only on that fleeting move after the two-square pawn push. Just glancing at the diagram, the odds are that it is illegal rather than legal.
I also just assumed I had the right to castle Kingside. (otherwise you wouldn't have claimed there was a mate in nine available)
Originally posted by heinzkatAny move that doesn't prevent an immediate Bxf8 results in a mate in 5:
I'd have to check that. In a game I would play Qxg6+ though!
What if just 1. ... a4? 2. Bxf8 and a mate via Qh6-g7. Of course, there will be a win very soon, but far too many variations and subvariations to work out!!
2. Bxf8 any (except ... Kxf8 3. Rh8# )
3, Rh8+ Kxh8
4. Qh6+ Kg8
5. Qg7#
So the only possible first moves for black are Re5 and queen moves. Qh6 loses to 2. Qxh6 any 3. Qg7#. Qe7 and Qxf6 both lose to 2. Rh8+ and it follows the line above. Therefore the only 1st moves for black are Qg7 and Re5. Admittedly there are a lot of variations in those but it's not quite as bad as first glance.
PaddyB: you are right, but try to fully write out all variations!
SwissGambit: I assume the puzzle is solved; retrogradic proof is still missing. The only proof I have, is you claiming there is a mate in 9 available; if Black's last move was anything other than a7-a5, White would not have had a mate in 9. So considering your statement 'White mates in 9', I assume Black's last move was a7-a5. In a similar way I assume White still has castling rights (at least on the Kingside).
White to move.
Originally posted by heinzkat1.Rf7+ Kg8 2.Re7 Ne5+ 3.fxe5 Rc8 4.exf6 Rf8 5.f7+ Rxf7 6.Rxf7 c2 7.Re7 c1R 8.Re8#
PaddyB: you are right, but try to fully write out all variations!
SwissGambit: I assume the puzzle is solved; retrogradic proof is still missing. The only proof I have, is you claiming there is a mate in 9 available; if Black's last move was anything other than a7-a5, White would not have had a mate in 9. So considering your statement 'White mates in 9', I on the Kingside).
[fen]5k2/3R4/2rN1pK1/3p4/5P2/2pnP1P1/7P/8 w - -[/fen]
White to move.
Matesauce.