In line with our back away slowly policy, here's a chess like one...
An 8x8 board with alternating black and white squares (a chess board) has two diagonally opposite corners removed.
You are given a set of rectangular dominos, each one can cover exactly two squares.
Is it possible to cover every remaining square on the board without stacking or going over the edge of the board.
Yes or no, and explain your logic.
Originally posted by agrysonNO! because each domino occupies both a black and white square at the same time, therefore with two of the same color square removed, only 30 dominoes could fit on the board. the 31st is excluded!!
In line with our back away slowly policy, here's a chess like one...
An 8x8 board with alternating black and white squares (a chess board) has two diagonally opposite corners removed.
You are given a set of rectangular dominos, each one can cover exactly two squares.
Is it possible to cover every remaining square on the board without stacking or going over the edge of the board.
Yes or no, and explain your logic.
Thank you.
edit: heard it before, very easy.
Ok, here's one...
To pay off his gambling debts a father has bet his daughter in a game of chance.
A merchant is to put a black stone and a white stone in a sack, the girl is to remove one stone. If it is white, the debt is cleared and the daughter goes home.
If it is black, the debt is cleared and she is now the property of the merchant.
The girl notices that the merchant has put two black stones in the sack but is not allowed to tell anyone. (part of the wager)
What is the probability that she can escape her predicament and why?
Originally posted by agrysonhave the merchant say the stone that is left in the bag.
Ok, here's one...
To pay off his gambling debts a father has bet his daughter in a game of chance.
A merchant is to put a black stone and a white stone in a sack, the girl is to remove one stone. If it is white, the debt is cleared and the daughter goes home.
If it is black, the debt is cleared and she is now the property of the merchant.
The girl notice ...[text shortened]... yone. (part of the wager)
What is the probability that she can escape her predicament and why?
He will say black in which case everyone else will think she has chosen white, under the circumstances she is to be let go.
Originally posted by agrysonI don't ask the questions here. I answer them.
Well aren't you a wet towel!
Go on, throw one at me... (a question, not a wet towel)
But here's one for the hell of it.
WIthout the aid of any measuring device,
How can you use a transparent 16-oz mug to measure a volume of water that is exactly 8 oz.?
Originally posted by agrysonAll you have is one mug and a water spout of some sort. That is it. You have nothing else on hand...other than your body parts.
Fair enough, but as regards the question, all I have is the one jug, no other items other than the water?
edit: for the purpose of this exercise, we shall say that this mug is a perfect cylinder.
Originally posted by agrysoneasier answer.
Here goes, put in the water to be measured, draw a mark on the outside, pour this into another receptacle. Fill the jug to the mark with water, then put the original water back in. if it comes to the top, I know I had exactly 8 oz. (ooh, I hate imperial measures!)
fill the mug about 2/3 full of water. then tilt it so the water pours off. When the water level reaches the same height as the uplifted mug bottom, then the vessel is indeed exactly half full.
edit: no body parts required!! that was just to throw you off!!!!