A Thread for the Superintelligent

Originally posted by agryson
In line with our back away slowly policy, here's a chess like one...
An 8x8 board with alternating black and white squares (a chess board) has two diagonally opposite corners removed.
You are given a set of rectangular dominos, each one can cover exactly two squares.
Is it possible to cover every remaining square on the board without stacking or going over the edge of the board.

No. That is simple. Here is one for you:

Person A says "you are dumb"
Person B says "Person A is lying"
Person C says "Person B is either telling the truth or lying"

Which one is telling the truth?

like I said guys, no sudden movements...

Originally posted by agryson
Gimme a break, I'm an Irishman in Paris and the Guinness here is crap. Besides, it was a hard day at the office.

At least the cheap wine is not so bad! 😉

Tell me about it! Even the cheap stuff is good!

Person A says "you are dumb"
Person B says "Person A is lying"
Person C says "Person B is either telling the truth or lying"

Which one is telling the truth?

None of them, since "you are dumb" is not a matter of fact, but opinion. But if it were a matter of fact, then C would be telling the truth; B and A would be nondeterminable, except that one is telling the truth and the other is lying.

Originally posted by agryson
move the two head matches so that they're pointing 'into' the body?

Exactly. Just because it has to face the other way, it doesn't mean it has to turn its body. It just has to turn its head, which is made up of two matches.

Sweet...

Problem1:

| | | | | |

these represent six matches. add five to give me nine.


Problem 2:

show to me before I show to you, that half of twelve is indeed seven.

problem 1:

I I I I I I + I I I
the plus is two matches, giving you nine.

Problem two... sticking with matches for no good reason...

IZ a rough twelve in matches, made of four matches, half this number is two which is done by removing the one and the bottom of the 2

7

1: Add a match diagonally beteen the first two, another one diagonally between the fourth and fifth, and another three attached horizontally to the sixth one: |\| | |\| E

2: X|| - draw the line of symmetry to cut it in half, and you get V||

Now use exactly six matches to make four congruent equilateral triangles whose side length is the length of a match.

Originally posted by Jirakon
1: Add a match diagonally beteen the first two, another one diagonally between the fourth and fifth, and another three attached horizontally to the sixth one: |\| | |\| E

2: X|| - draw the line of symmetry to cut it in half, and you get V||

Now use exactly six matches to make four congruent equilateral triangles whose side length is the length of a match.

its a tetrahedron.

three for the base and three standing erect at 60 degrees each.

GOtcha on that one.