Originally posted by HolyTIsn't this the same as my answer but with a lot more words to say it?
"Detecting" is just given in this question to indicate that you are somehow aware that there would be a wave front propogating ahead of the other ship. It could be by pre-arrangement with the other ship; it doesn't really matter.
The rocket and light example is not possible in the same way as the boat and wake example. Relative to you (in the trailing roc ...[text shortened]... hip is traveling at something less than the speed of light. Still, you'll never catch up.
Originally posted by coquetteNo, because the shorter answer had no discussion about why the situations are different. There was no discussion about the principles of relativity that apply to the situation at hand (speed of light the same to any observer) but not to the boat scenario. And the "detecting" issue, which was the only portion that the shorter answer addressed, was not the meat of the question; it was just a matter of setting up the scenario.
Isn't this the same as my answer but with a lot more words to say it?
Originally posted by RamnedOK< I'm only on page 8 so I'm gonna take a guess before looking in the back of the book! I'm gonna say the frequency is exactly the same! My reasoning is that this question is the same as the one where you have a car smash into a concrete abuttment, or TWO cars hit each other while weighing the same and traveling in opposite directions at exactly the same speed as in the 1st experiment. The result is identical! NOW I'll peek and see if I'm right!
[b]13. An object is hung on a spring, and the frequency of oscilation of the system, f, is measured. The object, a second identical object, and the spring are carried to space in the Space Shuttle. The two objects are attached to the ends of the spring, and the system is taken into space on a space walk. The spring is extended, and the system is released to o ...[text shortened]... e frequency of oscillation for this system, in terms of f?
There's the question again.[/b]