2018 International Mathematical Olympiad

Nice proof, D

Maths is common ground!

Isn't another way

21n + 4/ 14n + 3 = 3/2 - 1/2 ( 1/4n + 3) a few missing brackets


So, LHS = 1/2 ( 3 - 1/(4n + 3))

The 1/2 and 3 can be disregarded, and the algebraic fraction is 'under 1', so clearly cannot be simplified

Qed

A little confused as to why my post a couple up, offering a perfectly reasonable alternative 'proof' to D64's has been given a 'thumbs down'.

Who would do such a thing?

Hmmmm

Originally posted by @blood-on-the-tracks
A little confused as to why my post a couple up, offering a perfectly reasonable alternative 'proof' to D64's has been given a 'thumbs down'.

Who would do such a thing?

Hmmmm

I think you know the answer my friend.

It's the one who's fragile ego feels threatened when not being seen as the most brilliant person in the room.

I'm beginning to realize that the egos of chess players and "wannabe" writers are insatiably hungry.

Sort of like multiple cats in a home; they piss and whine until they have the most attention-advantageous territory all to themselves.

The post that was quoted here has been removed

It is correct .

I divided your algebraic fraction to show that it is equal to
1/2 ( 3 - 1/(14n+3)

To check my algebra, I welcome you to find time to work with the above expression and it will produce your original fraction.

You were wrong in your speculation. I do not need to alter anything I wrote.

And my final statement that THIS cannot be 'cancelled'in any way is also correct.

And no one can take that away from me

It is YOU who shows ignorance.

Now thsn, this 'thumbs down '

Wonder who?

Nit picking in the extreme.

Writing algebraic fractions in this format requires a tedious use of brackets.

I tidied it all up with my 'thus LHS =' in the original post.

Are you saying that I am incorrect in stating your fraction =

1/2 (3 - 1/(14n +3)) ?

That result is now stated for a third time.

Besides, I am more interested in who thumbed down my original post.

Any ideas?

The post that was quoted here has been removed

I see you edited

Do I?

If you would like to produce a counter example where 1/(14n + 3) or
3 minus that expression CAN be simplified (choose your 'n' from infinity integers), then I will withdraw.

Do I need to explain why 1 over an integer cannot be cancelled?

Or that n/(an +/- 1) cannot be simplified, a being any integer ?

How far back do I have to go? Basic factorisation explained.?

Thanks for marking my answer. I prefer the judgement of my lecturers at my university.

How come you can assume that your proof doesn't need full explanation and mine does?

Now then, this thumbs down. Ok. I will ask

Was it you?