Colored balls in a bag

Originally posted by eldragonfly
No, you are mistaken.

1) last two balls could be black - last ball = black

2) last two balls could be white - last ball = white

3) last two balls could be black and white - last ball = black.

4) clearly, there is no solution.

"1) last two balls could be black - last ball = black"

no. Two black balls = white

Originally posted by Mephisto2
"1) last two balls could be black - last ball = black"

no. Two black balls = white

That fails when the first draw is two black balls. So you have a nonsensical problem description. Unless you want to redefine the problem.

Originally posted by eldragonfly
That fails when the first draw is two black balls. So you have a nonsensical problem description. Unless you want to redefine the problem.

please elaborate. This is above my understanding level.

Originally posted by Mephisto2
please elaborate. This is above my understanding level.

i believe it.

1) brown paper bag contains 50 marbles - 25 white & 25 black

2) draw two marbles at random

3) pick two black marbles. paperbag now contains 48 marbles

4) It is impossible to return 1 white marble as you have 2 black marbles in your hand

[If you draw two white balls, or two black balls, you place a white ball in the bag.]

5) Your experiment is flawed may never get off the ground. That is why i asked for a modification of the original problem.

lol

Originally posted by eldragonfly
i believe it.

1) brown paper bag contains 50 marbles - 25 white & 25 black

2) draw two marbles at random

3) pick two black marbles. paperbag now contains 48 marbles

4) It is impossible to return 1 white marble as you have 2 black marbles in your hand

[If you draw two white balls, or two black balls, you place a white ball in the bag.]

...[text shortened]... ed may never get off the ground. That is why i asked for a modification of the original problem.

The problem says nothing of "returning". It is about replacing the last two drawn marbles with one marble. If the first draw is two black marbles, you replace them with a white marble.

Originally posted by Bowmann
lol

This time I agree.

Originally posted by Mephisto2
This time I agree.

Then you're right for once 😵

Originally posted by Bowmann
Then you're right for once 😵

I disagree.

Originally posted by rheymans
The problem says nothing of "returning". It is about replacing the last two drawn marbles with one marble. If the first draw is two black marbles, you replace them with a white marble.

You're not paying attention. Redefine the problem or admit you have a faulty definition.

Originally posted by eldragonfly
You're not paying attention. Redefine the problem or admit you have a faulty definition.

It seems to me that you are not paying attention. And being arrogant like this won't help you to convince anybody of the contrary.

Originally posted by eldragonfly
You're not paying attention. Redefine the problem or admit you have a faulty definition.

You're assuming that the marbles initially in the bag are the only marbles available.

The explanation you've been provided with shows this is a false assumption. There's only a problem with replacing the first two black balls with a white one if you assume that all the problem's white balls are in the bag!

Originally posted by Mephisto2
It seems to me that you are not paying attention. And being arrogant like this won't help you to convince anybody of the contrary.

Properly define the problem if you can. Or else tell me where you went to school.

Originally posted by eldragonfly
Properly define the problem if you can. Or else tell me where you went to school.

You're thicker than year-old yoghurt.

Originally posted by rheymans
You have a bag with 50 balls in it. 25 of the balls are white, and 25 are black. You draw two balls from the bag at a time. You don't know what color the balls are until you have removed them from the bag. If you draw two white balls, or two black balls, you place a white ball in the bag. If the draw is two balls of different color, you place a black ...[text shortened]... n white balls, and n black balls, when is the last ball white, and when is the last ball black?

1) bag with 50 balls in it - 25 black, 25 white

2) random selection

3) 2 alt = black 2 same = white

4) you place a white/black ball in the bag depending on selection

So several questions come to mind.

1) Where do the balls come from that are placed "in the bag?"

2) Is it the same bag or a different bag?

3) Do these "place in the bag" balls come from the same bag or not?

These question remains unanswered. i think i know why. 😕

From your shoddy definition it appears that the bag with 50 balls will just keep growing in size, ie., ad infinitum. So there won't be any "last" ball, let alone what color it might be.

If this is too complicated for you to understand - let me know. 🙄