Colored balls in a bag

Originally posted by XanthosNZ
Next problem:
How can you be so stupid?

Took him years of practice.

Originally posted by XanthosNZ
Next problem:
How can you be so stupid?

Sounds to me like you have issues. i only asked for somebody to "clean up" the original problem definition. Now all this tedious juvenile mudslinging.

Originally posted by adramforall
Took him years of practice.

Years of practice doing what? Explain yourself man.

Originally posted by eldragonfly
Years of practice doing what? Explain yourself man.

LOL! Classic.

EDIT: Welcome back, eldragonfly! 😀

Originally posted by rheymans
You have a bag with 50 balls in it. 25 of the balls are white, and 25 are black. You draw two balls from the bag at a time. You don't know what color the balls are until you have removed them from the bag. If you draw two white balls, or two black balls, you place a white ball in the bag. If the draw is two balls of different color, you place a black ...[text shortened]... n white balls, and n black balls, when is the last ball white, and when is the last ball black?

green😀

Hmm. if you have only have 50 balls and they're all in the bag
and your first draw is 2 black balls, you are obliged to place
a white ball in the bag.
However the only white balls are in the bag and the problem
states that you must draw two balls at a time. Thus putting forward
the possibility of drawing another 2 black balls.

The probability of this happening until 24 black balls have been
removed from the bag should be taken into account.


edit. If you have a green ball in one hand and a red one in the
other, what do you have?
ans. The incredible hulk at your mercy

Originally posted by Thequ1ck

However the only white balls are in the bag a

The problem doesn't make this claim.